3.164 \(\int \frac{1}{(-1+c^2 x^2)^{3/2} \sqrt{d-c^2 d x^2}} \, dx\)

Optimal. Leaf size=74 \[ \frac{d x \sqrt{c^2 x^2-1}}{2 \left (d-c^2 d x^2\right )^{3/2}}+\frac{\sqrt{c^2 x^2-1} \tanh ^{-1}(c x)}{2 c \sqrt{d-c^2 d x^2}} \]

[Out]

(d*x*Sqrt[-1 + c^2*x^2])/(2*(d - c^2*d*x^2)^(3/2)) + (Sqrt[-1 + c^2*x^2]*ArcTanh[c*x])/(2*c*Sqrt[d - c^2*d*x^2
])

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Rubi [A]  time = 0.0176594, antiderivative size = 91, normalized size of antiderivative = 1.23, number of steps used = 3, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {23, 199, 208} \[ \frac{x \left (d-c^2 d x^2\right )^{3/2}}{2 d^2 \left (1-c^2 x^2\right ) \left (c^2 x^2-1\right )^{3/2}}+\frac{\left (d-c^2 d x^2\right )^{3/2} \tanh ^{-1}(c x)}{2 c d^2 \left (c^2 x^2-1\right )^{3/2}} \]

Antiderivative was successfully verified.

[In]

Int[1/((-1 + c^2*x^2)^(3/2)*Sqrt[d - c^2*d*x^2]),x]

[Out]

(x*(d - c^2*d*x^2)^(3/2))/(2*d^2*(1 - c^2*x^2)*(-1 + c^2*x^2)^(3/2)) + ((d - c^2*d*x^2)^(3/2)*ArcTanh[c*x])/(2
*c*d^2*(-1 + c^2*x^2)^(3/2))

Rule 23

Int[(u_.)*((a_) + (b_.)*(v_))^(m_)*((c_) + (d_.)*(v_))^(n_), x_Symbol] :> Dist[(a + b*v)^m/(c + d*v)^m, Int[u*
(c + d*v)^(m + n), x], x] /; FreeQ[{a, b, c, d, m, n}, x] && EqQ[b*c - a*d, 0] &&  !(IntegerQ[m] || IntegerQ[n
] || GtQ[b/d, 0])

Rule 199

Int[((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> -Simp[(x*(a + b*x^n)^(p + 1))/(a*n*(p + 1)), x] + Dist[(n*(p +
1) + 1)/(a*n*(p + 1)), Int[(a + b*x^n)^(p + 1), x], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[p, -1] && (In
tegerQ[2*p] || (n == 2 && IntegerQ[4*p]) || (n == 2 && IntegerQ[3*p]) || Denominator[p + 1/n] < Denominator[p]
)

Rule 208

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-(a/b), 2]*ArcTanh[x/Rt[-(a/b), 2]])/a, x] /; FreeQ[{a,
b}, x] && NegQ[a/b]

Rubi steps

\begin{align*} \int \frac{1}{\left (-1+c^2 x^2\right )^{3/2} \sqrt{d-c^2 d x^2}} \, dx &=\frac{\left (d-c^2 d x^2\right )^{3/2} \int \frac{1}{\left (d-c^2 d x^2\right )^2} \, dx}{\left (-1+c^2 x^2\right )^{3/2}}\\ &=\frac{x \left (d-c^2 d x^2\right )^{3/2}}{2 d^2 \left (1-c^2 x^2\right ) \left (-1+c^2 x^2\right )^{3/2}}+\frac{\left (d-c^2 d x^2\right )^{3/2} \int \frac{1}{d-c^2 d x^2} \, dx}{2 d \left (-1+c^2 x^2\right )^{3/2}}\\ &=\frac{x \left (d-c^2 d x^2\right )^{3/2}}{2 d^2 \left (1-c^2 x^2\right ) \left (-1+c^2 x^2\right )^{3/2}}+\frac{\left (d-c^2 d x^2\right )^{3/2} \tanh ^{-1}(c x)}{2 c d^2 \left (-1+c^2 x^2\right )^{3/2}}\\ \end{align*}

Mathematica [A]  time = 0.0190215, size = 54, normalized size = 0.73 \[ \frac{\left (c^2 x^2-1\right ) \tanh ^{-1}(c x)-c x}{2 c \sqrt{c^2 x^2-1} \sqrt{d-c^2 d x^2}} \]

Antiderivative was successfully verified.

[In]

Integrate[1/((-1 + c^2*x^2)^(3/2)*Sqrt[d - c^2*d*x^2]),x]

[Out]

(-(c*x) + (-1 + c^2*x^2)*ArcTanh[c*x])/(2*c*Sqrt[-1 + c^2*x^2]*Sqrt[d - c^2*d*x^2])

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Maple [A]  time = 0.016, size = 94, normalized size = 1.3 \begin{align*}{\frac{\ln \left ( cx-1 \right ){x}^{2}{c}^{2}-\ln \left ( cx+1 \right ){x}^{2}{c}^{2}+2\,cx-\ln \left ( cx-1 \right ) +\ln \left ( cx+1 \right ) }{4\,cd \left ( cx-1 \right ) \left ( cx+1 \right ) }\sqrt{- \left ({c}^{2}{x}^{2}-1 \right ) d}{\frac{1}{\sqrt{{c}^{2}{x}^{2}-1}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(c^2*x^2-1)^(3/2)/(-c^2*d*x^2+d)^(1/2),x)

[Out]

1/4/(c^2*x^2-1)^(1/2)*(-(c^2*x^2-1)*d)^(1/2)*(ln(c*x-1)*x^2*c^2-ln(c*x+1)*x^2*c^2+2*c*x-ln(c*x-1)+ln(c*x+1))/d
/c/(c*x-1)/(c*x+1)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{-c^{2} d x^{2} + d}{\left (c^{2} x^{2} - 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^2-1)^(3/2)/(-c^2*d*x^2+d)^(1/2),x, algorithm="maxima")

[Out]

integrate(1/(sqrt(-c^2*d*x^2 + d)*(c^2*x^2 - 1)^(3/2)), x)

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Fricas [A]  time = 2.32747, size = 645, normalized size = 8.72 \begin{align*} \left [\frac{4 \, \sqrt{-c^{2} d x^{2} + d} \sqrt{c^{2} x^{2} - 1} c x -{\left (c^{4} x^{4} - 2 \, c^{2} x^{2} + 1\right )} \sqrt{-d} \log \left (-\frac{c^{6} d x^{6} + 5 \, c^{4} d x^{4} - 5 \, c^{2} d x^{2} - 4 \,{\left (c^{3} x^{3} + c x\right )} \sqrt{-c^{2} d x^{2} + d} \sqrt{c^{2} x^{2} - 1} \sqrt{-d} - d}{c^{6} x^{6} - 3 \, c^{4} x^{4} + 3 \, c^{2} x^{2} - 1}\right )}{8 \,{\left (c^{5} d x^{4} - 2 \, c^{3} d x^{2} + c d\right )}}, \frac{2 \, \sqrt{-c^{2} d x^{2} + d} \sqrt{c^{2} x^{2} - 1} c x -{\left (c^{4} x^{4} - 2 \, c^{2} x^{2} + 1\right )} \sqrt{d} \arctan \left (\frac{2 \, \sqrt{-c^{2} d x^{2} + d} \sqrt{c^{2} x^{2} - 1} c \sqrt{d} x}{c^{4} d x^{4} - d}\right )}{4 \,{\left (c^{5} d x^{4} - 2 \, c^{3} d x^{2} + c d\right )}}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^2-1)^(3/2)/(-c^2*d*x^2+d)^(1/2),x, algorithm="fricas")

[Out]

[1/8*(4*sqrt(-c^2*d*x^2 + d)*sqrt(c^2*x^2 - 1)*c*x - (c^4*x^4 - 2*c^2*x^2 + 1)*sqrt(-d)*log(-(c^6*d*x^6 + 5*c^
4*d*x^4 - 5*c^2*d*x^2 - 4*(c^3*x^3 + c*x)*sqrt(-c^2*d*x^2 + d)*sqrt(c^2*x^2 - 1)*sqrt(-d) - d)/(c^6*x^6 - 3*c^
4*x^4 + 3*c^2*x^2 - 1)))/(c^5*d*x^4 - 2*c^3*d*x^2 + c*d), 1/4*(2*sqrt(-c^2*d*x^2 + d)*sqrt(c^2*x^2 - 1)*c*x -
(c^4*x^4 - 2*c^2*x^2 + 1)*sqrt(d)*arctan(2*sqrt(-c^2*d*x^2 + d)*sqrt(c^2*x^2 - 1)*c*sqrt(d)*x/(c^4*d*x^4 - d))
)/(c^5*d*x^4 - 2*c^3*d*x^2 + c*d)]

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (\left (c x - 1\right ) \left (c x + 1\right )\right )^{\frac{3}{2}} \sqrt{- d \left (c x - 1\right ) \left (c x + 1\right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c**2*x**2-1)**(3/2)/(-c**2*d*x**2+d)**(1/2),x)

[Out]

Integral(1/(((c*x - 1)*(c*x + 1))**(3/2)*sqrt(-d*(c*x - 1)*(c*x + 1))), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\sqrt{-c^{2} d x^{2} + d}{\left (c^{2} x^{2} - 1\right )}^{\frac{3}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c^2*x^2-1)^(3/2)/(-c^2*d*x^2+d)^(1/2),x, algorithm="giac")

[Out]

integrate(1/(sqrt(-c^2*d*x^2 + d)*(c^2*x^2 - 1)^(3/2)), x)